By Deborah Hopkinson

ISBN-10: 0375867325

ISBN-13: 9780375867323

For years Dickens stored the tale of his personal formative years a mystery. but it's a tale worthy telling. For it is helping us have in mind how a lot all of us may possibly lose whilst a child's desires don't come precise . . . As a baby, Dickens was once pressured to continue to exist his personal and paintings lengthy hours in a rat-infested blacking manufacturing unit. Readers could be drawn into the winding streets of London, the place they're going to learn the way Dickens received the foundation for lots of of his characters. The 2 hundredth anniversary of Dickens's beginning is February 7, 2012, and this story of his little-known boyhood is the appropriate option to introduce youngsters to the nice writer. this is old fiction at its creative top.

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X , y creates an array whose leading items are the items of x and whose trailing items are the items of y; in other words, it concatenates x and y . 1 2 3 , 6 1 2 3 6 1 2 3 , 1 2 3 1 2 3 1 2 3 4 , 6 4 6 1 2 3 , 0$6 1 2 3 (i. 2 3) , (i. 3 3) 0 1 2 3 4 5 0 1 2 3 4 5 6 7 8 In the last example the items of x and y are 3-element lists, so x , y is a list of 3element lists, containing the items of x followed by the items of y . Dyad , has infinite rank, which means that it applies to its operands in their entirety and so its detailed operation is defined not by the implicit looping we have been learning, but instead by the definition of the verb in the Dictionary.

1 0 1 5 Yes, they seem to perform as advertised. They can be applied to arrays: ]a =. #: 5 9 0 1 0 1 1 0 0 1 Look: the result is not a rank-1 list, but rather a rank-2 array, where each item has the binary representation of one operand value (and notice, an extra leading zero was added to the representation of 5). The little trick with ]a =. will be explained later, but for now just think of ]a =. as 'assign to a and display the result'. With a assigned, we have: #. a 5 9 This seems to be the desired result, but on reflection we are puzzled: how did the interpreter know to apply #.

X + y addition x - y subtraction (y operates on x to match the mathematical definition) x * y multiplication x % y division Note that the slash has another use, so % is division. You don't have to worry about division by zero: it produces _ (infinity) or __ (negative infinity) except for 0%0, which yields 0 . x ^ y exponentiation (x to the power y). 0^0 yields 1 . x ^. y logarithm (base-x logarithm of y) x | y modulus (remainder when y is divided by x . For the longest time I had trouble remembering dyad |; it seemed that the divisor should be y by analogy to dyad % .

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A Boy Called Dickens by Deborah Hopkinson

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